Advantages of a personal area network

Functions of barriers include (mark all that apply): A. Define boundaries B. Design layout C. Deny access D. Delay access

gayaneshka [121]

Answer:

A. Define boundaries

C. Deny access

D. Delay access

Explanation:

A barrier is a material or structure used to prevent or block access. Barriers can either be natural or structural and are used for many purposes usually for security reasons. The following are functions of barriers either natural or structural:

Define areas of boundaries
Delay or slow access. Example is the use of speed bumps to slow down vehicles.
Provide access to entrances such as the use of gates
Deny access to unauthorized personnel and allowing authorized personnel.

4 0

3 years ago

The Turing test consists of a person asking written questions of a person and a computer. If the questioner can't tell which one

Juliette [100K]

Answer:

intelligence

Explanation:

According to my research on information technology, I can say that based on the information provided within the question if this happens then we can say that the computer has attained intelligence. This is because this is a test developed by Alan Turing in 1950, in order to observe a machine's ability to exhibit intelligent behavior equal to, or indistinguishable from, that of a human.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0

3 years ago

If you created a variable called name, what data type would that value be? Group of answer choices a float a string a Boolean an

Semenov [28]

I think its an integer

8 0

3 years ago

Read 2 more answers

Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0

3 years ago

Write a MIPS assembly language program that accomplishes the following tasks:The program will prompt the user to enter an intege

Svetlanka [38]

Answer:

Here's the code below

Explanation:

# All the comment will start with #

# MIPS is assembly language program.

# we store the all the data inside .data

.data:

k: .asciiz "Enter the kth value:\n"

.text

.globl main

li $s0, 0 # $s0 = 0

li $t0, 0 # $t0 = 0

la $n0, k # $n0 is kth value address

syscall # call print_string()

li $v0, 0 # $v0

syscall

move $n0, $v0 # $a0 = user input or "int n"

addi $sp, $sp, -4 # move the stack pointer down

sw $ra, 0 ($sp) # save the return address for main

jal fncheck # call fncheck(n);

fncheck:

beq $n, 0, fnfirst #if n==0 then fnfirst

ble $n0, 5, fnrec # if (n <=5) then 5

bge $n0, 5, fnjoke

#first function for n 0 and 1

fnfirst:

li $t0, 0 # initialize $t0 = 0

addi $t0, $t0, 20 # $t0 = 20

move $v0, $t0 # return 20

jr $ra

#function to execute 5*function1(n-2) + n;

fnrec:

sub $sp, $sp, 12 # store 3 registers

sw $ra, 0($sp) # $ra is the first register

sw $n0, 4($sp) # $n0 is the second register

addi $n0, $n0, -2 # $a0 = n - 2

jal function1

sw $v0, 8($sp) # store $v0, the 3rd register to be stored

lw $n0, 4($sp) # retrieve original value of n

lw $t0, 8($sp) # retrieve first function result (function1 (n-2))

mul $t0, $t0, 5 # $t0 = 5 * function1(n-2)

add $v0, $v0, $t0

lw $ra, 0($sp) # retrieve return address

addi $sp, $sp, 12

jr $ra

#function to print joke

fnjoke:

la "Joke section"

4 0

4 years ago