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4 years ago

Daniel had $28 to spend at the fair. If the admission to the fair is $8 and the rides cost $2

Mathematics

1 answer:

xeze [42]4 years ago

7 0

A. Write an inequality that represents Daniel’s situation.

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John's Bikes uses the retail inventory method. Sales at retail were $120,000. Net purchases were $68,000 at cost and $124,000 at

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The answer will be a

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3 years ago

Let p(x) = 7x + 5 and r(x) = x - 1. Find and evaluate (r x p) (5)

quester [9]

Answer: 39

Step-by-step explanation:

Given

P(x)=7x+5

r(x)=x-1

r(p(x))=7x+5-1=7x+4

so, r(p(5))

$\Rightarrow r(p(5))=7\times 5+4=35+4=39$

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3 years ago

A box contains three pen, two markers and a highlighter. Tara selects one item at random and does not return it to the box. She

kakasveta [241]

Two out of six probability

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4 years ago

Solve the following equations;- x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

$\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1$

Cross multiply ,

$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

$\sf\implies x^2+9^2-2.9.x = x +3 \\$

$\sf\implies x^2+81 - 18x = x -3$

Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

$\sf\implies ( x -13)(x-6)=0$

Equate both factors to 0 ,

$\sf\implies \boxed{\pink{\sf x = 13,6}}$

Hence the value of x is 13 or 6 .

7 0

3 years ago

Complete the missing value in the solution to the equation.^

svet-max [94.6K]

Answer:

Step-by-step explanation:

subtract 5y from both sides of the equation

6 0

3 years ago