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Elina [12.6K]
2 years ago
7

Need help with 5&6 please

Mathematics
2 answers:
TiliK225 [7]2 years ago
7 0
For #6
x^2 - 8x -33 = 0
(x + 3) * (x - 11) = 0


Nitella [24]2 years ago
7 0
# 5
h(t) = -16t^2 + 190
46 = -16t^2 + 190
subtract 190 from both sides
-144 = - 16t^2
divide both sides by -16 
9 = t^2
square root both sides
3 = t
t = 3 seconds

# 6
f(x) = x^2 - 8x - 33
f(x) = (x - 11)(x + 3)
f(x) = (x - 4)^2 - 49 vertex (4,-49)
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Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
2 years ago
1. what would the effect have been on the calculated formula weight ([9] above) of your unknown as compared to the true formula
kramer

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

To know more about copper, refer to this link:

brainly.com/question/1543891

#SPJ4

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9 months ago
How do you solve log x = 4?
antoniya [11.8K]
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10^4=x

We can now solve for x.

This means that x= 10,000
4 0
3 years ago
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