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andrew-mc [135]
3 years ago
9

Please answer this correctly

Mathematics
1 answer:
viva [34]3 years ago
3 0

Answer:

2/5

Step-by-step explanation:

Let's find the probability of each condition first.

For P(4), there is only one option: 4. This is 1 out of 5.

For P(even), this includes 4 and 6. However, we already had 4 from our last condition so we can remove this option. This is again 1 out of 5.

Adding them together, we will get 2/5.

The answer is 2/5

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3x – 8y &gt; 32<br> what the answer
Sonbull [250]

Answer:

y < 3/8x-4

Step-by-step explanation:

3 0
3 years ago
I need help this question?
Olegator [25]

Answer: the first option is the correct answer.

Step-by-step explanation:

Let x represent the number of necklaces that he makes in a year.

Profit = Revenue - cost

The cost of making each necklace is $5. In making necklaces in a year, the fixed cost is $5000. This means that the total cost of making x necklaces in a year is

5x + 5000

Sam sells each necklace for $10 each. This means that the total amount made from selling x necklaces is $10x.

For Sam to make profit of $1000 in a year, the number of necklaces that she must sell would be

1000 = 10x - (5x + 5000)

1000 = 10x - 5x - 5000

10x - 5x = 1000 + 5000

5x = 6000

x = 6000/5

x = 1200

7 0
3 years ago
The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
3 years ago
Total power generated by wind worldwide doubles every 3 years. In a particular year, the world wind-generating capacity was abou
IceJOKER [234]
<span>You are given the sum of the power created by wind worldwide which doubles every 3 years. In one an unknown year, the world wind generating capacity was about 91 thousand megawatts. You are asked for the growth rate. the growth rate formula is given below:

growth rate = (present / past)^(1/n)
2 = (present/91MW)^(1/3)
the present power is 728MW</span>
7 0
3 years ago
Find an equation of variation in which y varies directly as x and y=1 when x=0.5. Then find the value of y when x = 14.
FromTheMoon [43]

<u>Part 1</u>

The value of y is twice that of x, so the equation is y = 2x.

<u>Part 2</u>

Substituting in x = 14, we get y = 2(14) = 28.

8 0
2 years ago
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