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IceJOKER [234]
2 years ago
6

Angle JKL is 54 degrees. What is the measure of angle MKL? *

Mathematics
1 answer:
hoa [83]2 years ago
6 0

Answer:

MKL = 36°

Step-by-step explanation:

(3x + 6) + (6x + 12) = 54°

3x + 6x + 6 + 12 = 54

9x + 18 = 54

9x = 54 - 18

9x = 36

x = 36/9

x = 4

MKL = 6x + 12

MKL = 6(4) + 12

MKL = 24 + 12

MKL = 36°

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alina1380 [7]

Answer:

Therefore the friends will have to buy 511 feet of fence (rounding up) or 510 feet of fence ( to the nearest foot).

Step-by-step explanation:

i) perimeter of rectangular yard = 319 feet

ii) perimeter of yard of friends = \frac{8}{5} \times 319 = 510.4

iii) Therefore the friends will have to buy 511 feet of fence or 510 feet of fence ( to the nearest foot).

6 0
3 years ago
The figure shown below is a rhombus. Give the angle value (numerical, not the letters.
Rzqust [24]

Answer:

90 deg

Step-by-step explanation:

Recall that for a rhombus, the diagonals always intersect at right angles.

Hence angle PXM is 90 deg

6 0
3 years ago
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Round inglés
Andrew [12]

Answer:

13. 200

14. 8,300

15. 500

16. 2,500

Step-by-step explanation:

13. It is more than 4

14. It is more than 4

15. It is less than 4

16. It is more than 4

5 0
3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
Based on experience, the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal
Veronika [31]

Answer:

a) 3.128

b) Yes, it is an outerlier

Step-by-step explanation:

The standardized z-score for a particular sample can be determined via the following expression:

z_i = {x_i -\bar x}/{s}

Where;

\bar x = sample means

s = sample standard deviation

Given data:

the mean shipment thickness (\bar x) = 0.2731 mm

With the standardized deviation (s) = 0.000959 mm

The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression

z_i = {x_i -\bar x}/{s}

z_i = {0.2761-0.2731}/{ 0.000959}

z_i = 3.128

b)

From the standardized z-score

If [z_i < 2]; it typically implies that the data is unusual

If [z_i > 2]; it means that the data value is an outerlier

However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.

6 0
3 years ago
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