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IceJOKER [234]
3 years ago
6

Angle JKL is 54 degrees. What is the measure of angle MKL? *

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer:

MKL = 36°

Step-by-step explanation:

(3x + 6) + (6x + 12) = 54°

3x + 6x + 6 + 12 = 54

9x + 18 = 54

9x = 54 - 18

9x = 36

x = 36/9

x = 4

MKL = 6x + 12

MKL = 6(4) + 12

MKL = 24 + 12

MKL = 36°

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If you round (to the hundreths), it would be 97/100

Without rounding, it is 96/100 which simplifies to 24/25
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3 years ago
Sam and Cam have a lawn-mowing service. Their first job tomorrow morning is one that usually takes Sam 40 minutes to do alone, o
SVETLANKA909090 [29]
Sam can his job in 20 min. So he can do the whole job at the rate of 1 job in 20 minutes.
So he does 1/20 of the job per minute.

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Working together how long does it take?
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1/20*x + 1/30*x = 1 job done
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Multiply everything by 60 to get rid of the fractions.
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7 0
2 years ago
There are 28.35 grams in an ounce and 2.21 pounds in a kilogram. Miriam converted 7 kilograms to ounces, but her answer is not c
Montano1993 [528]

Answer:

The conversion from kilograms to ounce

Step-by-step explanation:

Kilograms to ounce

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4 0
3 years ago
Derek adds water to a pool at a rate of 12 gallons per minute and then reduces the rate to to 8 gallons per minute. Derek adds w
madam [21]

Answer:

At the faster rate (12 gallons per minute)

Time = 60t minutes

At the slower rate (8 gallons per minute)

Time = 120 - 60t minute

Step-by-step explanation:

From the question,

  • Derek adds water to a pool at a rate of 12 gallons per minute and then reduces the rate to 8 gallons per minute.

From the statement above, it means 12 gallons per minute is the faster rate and

8 gallons per minute is the slower rate

Also,

He adds water to the pool for a total of 2 hours. That is, the total time he spends adding water to the pool at both rates is 2 hours.

From the question, let t be the time in hours that he adds water to the pool at the faster rate. That is,

At the rate of 12 gallons/minute

Time = t hours (Convert to minute)

(NOTE: 1hour = 60 minute)

Time = t × 60 minute

Time = 60t minute

Since the total time spent was 2 hours, then

The time spent when adding water at the rate of 8 gallons / minute will be

Time = 2 - t hours (convert to minute)

Time = (2 - t) × 60 minutes

Time = 120 - 60t minutes

Hence, the algebraic expression for the time he spends adding water to the pool at the faster rate is

Time = 60t minutes

and for the slower rate

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6 0
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Evaluate the expression.<br><br> log,7(1/49)
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Answer:

0.01724

Step-by-step explanation:

calculator

4 0
3 years ago
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