Figure X is greater than figure Y by 9 units. 3•3•3= 27 while 3•3•4= 36
Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:
![2(w+w+200)=1040](https://tex.z-dn.net/?f=2%28w%2Bw%2B200%29%3D1040)
Let us solve for w.
![2(2w+200)=1040](https://tex.z-dn.net/?f=2%282w%2B200%29%3D1040)
![4w+400=1040](https://tex.z-dn.net/?f=4w%2B400%3D1040)
![4w+400-400=1040-400](https://tex.z-dn.net/?f=4w%2B400-400%3D1040-400)
![4w=640](https://tex.z-dn.net/?f=4w%3D640)
![\frac{4w}{4}=\frac{640}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4w%7D%7B4%7D%3D%5Cfrac%7B640%7D%7B4%7D)
![w=160](https://tex.z-dn.net/?f=w%3D160)
Therefore, the width of the football field is 160 feet.
Upon substituting
in expression
, we will get length of field as:
![w+200\Rightarrow 160+200=360](https://tex.z-dn.net/?f=w%2B200%5CRightarrow%20160%2B200%3D360)
Therefore, the length of the football field is 360 feet.
The inflation is 1,950-1870=80
if 1870 is the 100% 80 is the x%
1870/100=80/x
x=100(80)/1870
x=8000/1870
x=4.27
but you can round it to 4.3
Answer:(5-7)²
Step-by-step explanation: as h(x)=x-7 and g(x)=x²
so, goh(x)=g(h(x))
=g(x-7)
=(x-7)²
hence, goh(5)=(5-7)²