<u>Answer:</u>
225 ft²
<u>Steps:</u>
(20×10)+5² = 200+25 = 225 ft²
We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

Combine like terms and solve for x.

Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
Answer:2/20 =
2 ÷ 20 =
0.1 =
0.1 × 100/100 =
0.1 × 100% =
Step-by-step explanation:
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