C) 400 times larger is the answer
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.
<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2
p = -2, h=0, k=0</span><span>
focal width = |4*(-2)| = 8
The answer to your question is that the length of the focal width is equal to 8.</span>
Answer- 73
Remember PEMDAS
33 + 4 • (52-42)
(52-42)= 10
33+ 4•(10) -> 4(10)= 40
33+40 =73
3/5 = 6/x
3x = 30
x = 10
PLEASE pay attention in class, you basically asked every question on what seems to be homework
Answer:
x = 15
Step-by-step explanation:
cross multiply -->
8x = 120 *divide by 8 on both sides*
x = 15
CHECK:
5/8 + 15/24
multiply by 3 to get the second fraction