Your answer is 6%
because 6% =0.06 x 750 =45
45x 5 (years)=225
To find 10,000 more than 6,310, you add; so the answer is 16,310
Answer:
{HH, HT, TH, TT}
Step-by-step explanation:
The set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;
HH, HT
Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.
In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;
TH, TT
Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.
Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
Answer:
Subtracting 7
Step-by-step explanation:
<u><em>Given:</em></u>
<em>Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the third stack, and 24 plastic cups in the fourth stack. </em>
<u><em>To Find:</em></u>
<em>What kind of sequence is this?</em>
<u><em>Solve:</em></u>
<em>Let's make a table:</em>
<em />
<em>[1 stack] 45 </em>
<em>[2 stack] 38</em>
<em>[3 stack] 31</em>
<em>[4 stack] 24</em>
<em />
<em>Now all we have to do is subtract to see what each is:</em>
<em>45 - 38 = 7</em>
<em>38 - 31 = 7</em>
<em>31 - 24 = 7</em>
<em>Thus,</em>
<em>[1 stack] 45 ⇒ 7</em>
<em>[2 stack] 38 ⇒ 7 </em>
<em>[3 stack] 31 ⇒ 7 </em>
<em>[4 stack] 24 ⇒ 7 </em>
<em>Hence, each stack is going down by 7.</em>
<em />
<u><em>Kavinsky</em></u>
<em />
Answer:
no you can not but 4/0 on a number line
