All categories

2 years ago

Can a teacher at school make you take off your jacket of and not to enter the class with it

Mathematics

2 answers:

Stells [14]2 years ago

6 0

Answer:

No, he or she can't

Step-by-step explanation:

They can't because that's your personal stuff they can't make you do it unless you have your hood on then, yes they can.

sasho [114]2 years ago

3 0

Answer:

She can't make you do anything, however if it is a distraction to the class then yeah. I'm assuming it's your math teacher. she can make you take off anything on your head though

Step-by-step explanation:

You might be interested in

A certain television is advertised as a 58-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches t

ra1l [238]

Your answer will be 16

6 0

3 years ago

Read 2 more answers

Assume that A ABC= A POR. Which of the following congruence statements are correct? Check all that apply. A. AB = OR B. BE PO C.

yulyashka [42]

For congruence of triangles.

If;

$\Delta ABC\cong\Delta PQR$

Then the corresponding sides and angles will be equal.

$\begin{gathered} AB=PQ \\ BC=QR \\ AC=PR \\ \measuredangle A=\measuredangle P \\ \measuredangle B=\measuredangle Q \\ \measuredangle C=\measuredangle R \end{gathered}$

Only the above congruence statements are true.

Any options that has any of the above congruence statement is true.

3 0

10 months ago

Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north.

mylen [45]

G=t negative 320+f5 t=b

6 0

2 years ago

2 2 (2,2) 4 2 2 4 x -2 (1,-2)What is the slope

GarryVolchara [31]

Answer:

Step-by-step explanation:

8 0

3 years ago

A gumball machine has just been filled with 50 black, 150 white, 100 red and 100 yellow gum balls that have been thoroughly mixe

Andrew [12]

Exactly 33/532, or about 6.2% This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball. There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red. Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133. So the combined probability of both of the 1st 2 gumballs being red is 1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%

6 0

3 years ago