Answer:
Explanation:
The two triangles are similar what is the length of DE
No, it is impossible to determine the exact location of an electron. This is because electrons don't have a definite position, and direction of motion, at the same time and its movements are unpredictable
From our studies of the work of Professor Newton,
we have learned that
F = M a .
That is, the product of an object's mass and its acceleration
is equal to the net force acting on it.
An object in equilibrium is an object that has no acceleration.
In other words, it may be moving in a straight line at a speed
that does not change, or it may be just lying there before us.
In either case, since the object has no acceleration, we glance
at Newton's formula, and we instantly realize that the net force
on the object must be ZERO.
The object behaves just as if there were NO forces acting on it at all.
Answer:
F=(-4.8*10^22,0,0) N
Explanation:
<u>Given :</u>
We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°
Solution :
We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.
The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next
F=|F|cosФp (1)
Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet
F=|F|cosФp
=-4.8*10^22 N*p
<em>As this force is in one direction, we could get its vector as next </em>
F=(-4.8*10^22,0,0) N
F=(0,-4.8*10^22,0) N
F=(0,0-4.8*10^22) N
The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.
