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Likurg_2 [28]
3 years ago
9

A force of 20N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration?

Physics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer:

Explanation:

The two triangles are similar what is the length of DE

Anton [14]3 years ago
5 0

Answer:

ivvuvuvvucucufufufuvucuvucugufuf for fufufufuc

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Find the weight of an object of mass 5 kg
Elis [28]

Answer:

weight on earth is mg

which is 5*9.8

49 Newton

weight on moon is 1/6 th of weight on earth

1/6*49

8.166 Newton..

3 0
3 years ago
Read 2 more answers
If a conducting loop of radius 10 cm is onboard an instrument on Jupiter at 45 degree latitude, and is rotating with a frequency
Pepsi [2]

Answer:

a)  fem = - 2.1514 10⁻⁴ V,  b) I = - 64.0 10⁻³ A, c)    P = 1.38  10⁻⁶ W

Explanation:

This exercise is about Faraday's law

         fem = - \frac{ d \Phi_B}{dt}

where the magnetic flux is

        Ф = B x A

the bold are vectors

        A = π r²

we assume that the angle between the magnetic field and the normal to the area is zero

         fem = - B π 2r dr/dt = - 2π B r v

linear and angular velocity are related

        v = w r

        w = 2π f

        v = 2π f r

we substitute

        fem = - 2π B r (2π f r)

        fem = -4π² B f r²

For the magnetic field of Jupiter we use the equatorial field B = 428 10⁻⁶T

we reduce the magnitudes to the SI system

       f = 2 rev / s (2π rad / 1 rev) = 4π Hz

we calculate

       fem = - 4π² 428 10⁻⁶ 4π 0.10²

       fem = - 16π³ 428 10⁻⁶ 0.010

       fem = - 2.1514 10⁻⁴ V

for the current let's use Ohm's law

        V = I R

        I = V / R

         I = -2.1514 10⁻⁴ / 0.00336

         I = - 64.0 10⁻³ A

Electric power is

        P = V I

        P = 2.1514 10⁻⁴ 64.0 10⁻³

        P = 1.38  10⁻⁶ W

6 0
3 years ago
An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled duri
ICE Princess25 [194]

Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

d=ut+\dfrac{1}{2}at^2

d=10\times 8+\dfrac{1}{2}\times 3.5\times 8^2\\\\d=192\ m

So, the distance travelled by the object is 192 meters.

4 0
3 years ago
No links please, links never work, this is science not physics
stiks02 [169]

Answer:

b and c are the answers

A is an opinion, D is a superstitious belief because they haven’t found Jesus obviously

7 0
3 years ago
What can you use to determine whether the SATA port no which you are connecting the drive will also run at 6.0Gbps?
kolbaska11 [484]

Answer:

The answer is "use manual motherboard".

Explanation:

The motherboard is also known as the mainboard, it an electronic circuit board, that can connect with the CPU, RAM, and other networking equipment parts. It is also is known as a chipset, that differ widely in style, context, power source, height and performance (Form Factor).

All the data of the computer is stored memory, which checks into the motherboard, that the SATA port which you are connected to is still going to run at 6.0Gbps or not.

8 0
3 years ago
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