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Likurg_2 [28]
2 years ago
9

A force of 20N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration?

Physics
2 answers:
zloy xaker [14]2 years ago
7 0

Answer:

Explanation:

The two triangles are similar what is the length of DE

Anton [14]2 years ago
5 0

Answer:

ivvuvuvvucucufufufuvucuvucugufuf for fufufufuc

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11. Scientists put a sample of water into a sealed tank. Water can be a solid, liquid, or gas. At first, the water was a liquid.
leva [86]

Answer:

c . slower and started moving in place.

Explanation:

Matter can exist generally in three phases, as a solid, liquid or gas. But it can be transformed from one phase to another by the removal or application of heat energy.

The water was initially in a liquid form in the sealed tank until energy was transferred out of the substance. Thus, this causes a change of state in which the water turns to a solid. Whereby during the process, the molecules of the water moved slowly until they are fixed at a point, and vibrates individually at their individual point.

Therefore the molecules of water moved slower and stated moving in place (i.e vibrating at a point). The water turns to an ice.

3 0
3 years ago
A vertical spring (ignore its mass), whose spring constant is 1070 N/m, is attached to a table and is compressed 0.100 m.
harina [27]

I can not solve the problem if I do not have the mass.

3 0
3 years ago
Match these items.
horrorfan [7]
Iron oxide = small region within a magnet
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3 years ago
What are two ways thermal energy can be increased in a system?
MaRussiya [10]
Adding thermal energy
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3 0
3 years ago
The roller coaster car has a mass of 700 kg, including its passenger. If it is released from rest at the top of the hill A, dete
sweet [91]

Answer:

h = 18.75 m

Now when it will reach at point B then its normal force is just equal to ZERO

N_B = 0

F_n = 1.72 \times 10^4

Explanation:

Since we need to cross both the loops so least speed at the bottom must be

v = \sqrt{5 R g}

also by energy conservation this is gained by initial potential energy

mgh = \frac{1}{2}mv^2

v = \sqrt{2gh}

so we will have

\sqrt{2gh} = \sqrt{5Rg}

now we have

h = \frac{5R}{2}

here we have

R = 7.5 m

so we have

h = \frac{5(7.5)}{2}

h = 18.75 m

Now when it will reach at point B then its normal force is just equal to ZERO

N_B = 0

now when it reach point C then the speed will be

mgh - mg(2R_c) = \frac{1}{2]mv_c^2

v_c^2 = 2g(h - 2R_c)

v_c = 13.1 m/s

now normal force at point C is given as

F_n = \frac{mv_c^2}{R_c} - mg

F_n = \frac{700\times 13.1^2}{5} - (700 \times 9.8)

F_n = 1.72 \times 10^4

7 0
3 years ago
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