Answer:
<em>0.45 N</em>
Explanation:
<em>Let Recall that,</em>
<em> The power formula is: </em>
<em> P = E²/R </em>
Let A = the magnetic field
<em>Let L = length of wire = 9.00cm = 0.09 m </em>
let R = resistance of wire = 0.320 Ω
let v = velocity of the wire = 4 m/s
<em>Let E = across the wire voltage </em>
Let P = the power of the wire = 4.3 W
To Solve for E:
<em>The formula of E = √PR </em>
The Voltage from a magnetic field is given as,
E = vAL
We therefore Use E = E
√PR = vAL
to solve for A,
A= √PR/vL
BA= √4.3(0.32)/(4)(.09) -=0.173
A = 0.173 wA/m²
Let F be the pulling force
Let I be the current in the wire
P = I²R
<em>I = √P/R </em>
F = IAL
F = √P/RAL
F = √4.3/.32(0.173)(.09)
<em>F = 0.45N</em>
Answer:
Explanation:
in parallel combination equivalent resistence =
1/R=1/R1 + 1/R2
1/2=1/15+1/30
1/2=1*2+1*1/30
1/R=3/30
R*3=30*1
R=30/3
R=10 ohm
"You couldn't hear anything and it'd be hard to breathe.
The Earth likely couldn't survive without it." -Science Teacher