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Nataliya [291]
3 years ago
15

A painter can paint 180 square feet in 1/2 hour. how many feet can he paint in 2 hours

Mathematics
2 answers:
IgorC [24]3 years ago
7 0
Well 1/2 is one quarter of 2 hours. so if he can paint 180 square feet is 1/2 hour multiply it by four to get 2 hours.  so 180 times 4 is 720.
He can paint 720 square feet in 2 hours
Gre4nikov [31]3 years ago
3 0
Here is what you could do you could take the 180 and multiply by 2
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Find the area of a trapezoid with base 1 side = 10 base 2 side = 16 and 3​
mart [117]

Answer:

Area of Trapezoid is 39 unit²

Step-by-step explanation:

Given as :

For A Trapezoid

The measure of base side 1 = b_1 = 10 unit

The measure of base side 2 = b_2 = 16 unit

The height of the Trapezoid = h = 3 unit

Let  The Area of Trapezoid = A square unit

<u>Now, From Formula</u>

Area of Trapezoid = \dfrac{1}{2} × (sum of opposite base) × height

I.e A =  \dfrac{1}{2} × (b_1 + b_2) × h

Or, A =  \dfrac{1}{2} × (10 unit + 16 unit) × 3 unit

Or, A =  \dfrac{1}{2} × (26 unit) × 3 unit

Or, A =  \dfrac{1}{2} × 78 unit²

Or, A = \dfrac{78}{2} unit²

I.e A = 39 unit²

So, The Area of Trapezoid = A = 39 unit²

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6 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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