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fgiga [73]
3 years ago
6

Find the derivative of f(x) = 2x2 + 7x at -3. That is, find f'(-3).

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

Hello,

f'(-3) = -5

Step-by-step explanation:

f'(x) = 4 x + 7

f'(-3) = 4 (-3) + 7 = -12 + 7 = -5

or

f(-3) = 2 (-3)² + 7 (-3) = 18 - 21 = -3

f(-3 + h) = 2 (-3 + h)² + 7 (-3 + h)

= 2 (9 - 6h + h²) - 21 + 7h

= 18 - 12h + 2h²  - 21 + 7h

= 2h² - 5h - 3

( f(-3 + h) - f(-3) ) / h = 2h - 5

f'(-3) = lim h→0 ( f(-3 + h) - f(-3) ) / h = lim h→0 (2h - 5) = -5

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A= [ 1 -1 -1 ]

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[ 1 1 4 ]

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Find the co factor

| 2 3 | |-1 3 | |-1 2 |

| 1. 4. | |1 4 | |1. 1 |

|-1. -1 | |1 -1 | |1 -1

| 1. 4 | |1. 4| |1 1|

|-1. -1 | |1 -1 | |1. -1

|2. 3| |-1. 3| |-1 2|

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[3 5 -2 ]

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Reflect this along the diagonal( Keep 5,5 -2)

Then switching positions of other value

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SO

OPTION C

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