Answer:
x ≈ {0.653059729092, 3.75570086464}
Step-by-step explanation:
A graphing calculator can tell you the roots of ...
f(x) = ln(x) -1/(x -3)
are near 0.653 and 3.756. These values are sufficiently close that Newton's method iteration can find solutions to full calculator precision in a few iterations.
In the attachment, we use g(x) as the iteration function. Since its value is shown even as its argument is being typed, we can start typing with the graphical solution value, then simply copy the digits of the iterated value as they appear. After about 6 or 8 input digits, the output stops changing, so that is our solution.
Rounded to 6 decimal places, the solutions are {0.653060, 3.755701}.
_____
A similar method can be used on a calculator such as the TI-84. One function can be defined a.s f(x) is above. Another can be defined as g(x) is in the attachment, by making use of the calculator's derivative function. After the first g(0.653) value is found, for example, remaining iterations can be g(Ans) until the result stops changing,
Answer:
1.8 + 0.75
Step-by-step explanation:
1.80
+0.75
= 2.55
I think. :)
If I did this right it should be 8.
Answer:
7) x + 0.09x, where x is the price of the car
8) x + 0.05x where x is the price of clothing
9) It will take michael about 9.14 minutes to eat 32 cookies.
Step-by-step explanation:
7) 9% of x is the same as 0.09x, so you can write this:
x + 0.09x, where x is the price of the car
8) same thing for this one
x + 0.05x where x is the price of clothing
9) michael can eat cookies at a rate of 21 cookies per 6 minutes, or 
Because he will be eating them at the same pace, you can write an equation and solve for the variable:
= 
cross multiply the proportion:
21 × y = 32 × 6
solve:
21y = 192
y ≈ 9.14
It will take michael about 9.14 minutes to eat 32 cookies.
This works because they both simplify to 3.5 cookies per minute
= 3.5
= 3.5
Answer:
100000000
Step-by-step explanation:
Basic way to do this when using 10's 100's 1000's and up, count the number of zeros on the end and multiple the first regular number then add the zeros back :D