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belka [17]
3 years ago
14

A number is picked randomly in the range [0,7]. What is the probability that the number picked is between 3 and 5? What is the p

robability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5]?
Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

(1) 0.125

(2) 0.125

Step-by-step explanation:

The total number of possible outcomes is:

N = 8

(1)

Compute the probability that the number picked is between 3 and 5 as follows:

Number of Favorable outcomes = 1

The probability is:

P (Number picked is between 3 and 5) = 1/8 = 0.125

Thus, the probability that the number picked is between 3 and 5 is 0.125.

(2)

The number usually picked appears to be in in the range [3,5], i.e. the numbers could be, {3, 4 or 5}.

Number of Favorable outcomes = n (Number < 4 and within [3, 5]) = 1

P (less than 4 ∩ within [3, 5]) = 1/8 = 0.125

Thus, the probability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5] is 0.125.

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Answer:

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Step-by-step explanation:

hey there!

sine = opposite divided by hypotenuse

the opposite of angle 0 is 24 and the hypotenuse is 25 so sin 0 = 24/25

cosine = adjacent divided by hypotenuse

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2 years ago
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postnew [5]

Answer:

1- ( { 2 x - 1)}^{2} =  4x (1  - x )

Step-by-step explanation:

We want to to rewrite

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Use difference of two squares to get:

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This implies that:

{1}^{2} - ( { 2 x - 1)}^{2}  = (1 +( 2x - 1))(1  - (2x  - 1))

{1}^{2} - ( { 2 x - 1)}^{2}  = (1 + 2x - 1)(1  - 2x   + 1)

This finally simplifies to:

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Therefore the required product is

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3 0
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Option B is correct answer.

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ivanzaharov [21]

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