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Kamila [148]
3 years ago
8

Find the missing side lengths and leave your answers as radicals in the simplest form.

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0

Answer:

a = 4

b = 2√2

Step-by-step explanation:

First, we will calculate the sine of 45°, which is equal to the length of the opposite side (2√2) divided by the length of the hypotenuse (a).

sin 45° = 2√2 / a

a = 2√2 / sin 45°

We know than sin 45° = √2/2

a = (2√2) / (√2/2) = 4

Then, we calculate the tangent of 45°, which is equal to the length of the opposite side (2√2) divided by the length of the adjacent side (b).

tan 45° = 2√2 / b

b = 2√2 / tan 45°

We know that tan 45° = 1

b = 2√2 /  1 = 2√2

goblinko [34]3 years ago
3 0
Right triangle 45 45 90
so b = 2√2

and
a^2 = (2√2)^2 +  (2√2)^2
a^2 = 8 + 8 
a^2 = 16
a = 4
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Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
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Please note the { are supposed to span over both equations but it interfaces doesn't  allow it. Please see attachment for clarification.

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