E^(3x) = 3247
3x = log 3247
x = [log 3247]/3
Answer:
Step-by-step explanation:
Arithmetic sequence:
Here a is the first term and d is the common difference.
⇒ 
------------(I)
⇒ a + 19d = 100 ---------(II)
Subtract equation (I) from (II)
(I1) a + 19d = 100
(II) a + 13d = 46
<u>- - -</u>
6d = 54
d = 54 ÷ 6
Substitute d = 9 in equation(I) and find 'a',
a + 13*9= 46
a + 117 = 46
a = 46 - 117
a = -71
= -71 + 18
= -53
= -71 + 54
= -17
= -71 + 9*n - 1 *9
= -71 + 9n - 9
= -71 - 9 + 9n
= - 80 + 9n
Seven million, nine hundred thousand, 10 thousand, five thousand, eight hundred seventy eight,
or
seven million, nine hundred fifteen thousand, eight hundred seventy eight
The answer is 107
Vote Trump 2020
Answer:
YET
Step-by-step explanation:
TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.
TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.
D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.
SO, D IS DECRYPTED AS Y
GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.
K IS THEN DECRYPTED AS
K = J - I - H - G - F - E
K IS DECRPYTED AS E
GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS
A = Z - Y - X - W - V - U - T.
THUS, DKA IS DECRYPTED AS YET
