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3 years ago

Will the second method for determining volume (water displacement) work for ANY object or JUST an irregularly shaped one?

1 answer:

3 0

Finding the volume of regular geometric objects uses standard formulas. The volume of a box equals length times width times height, for example. Not every object, however, fits a formula. Water displacement is best only used for irregular shaped objects.

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[2071]State and explain Kohlrusch's law.

notsponge [240]

I have no idea how about it lol I t

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3 years ago

If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr

Savatey [412]

Answer:

The value of the heat capacity of the Calorimeter $C_c$ = 54.4 $\frac{J}{c}$

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water $m_w$ = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = $m_w C_w$ ΔT + $C_c$ ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 + $C_c$ × 11.24

611.37 = $C_c$ × 11.24

$C_c$ = 54.4 $\frac{J}{c}$

This is the value of the heat capacity of the Calorimeter.

5 0

3 years ago

Question 1

sdas [7]

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3 0

3 years ago

For each given [H3O+] or [OH-], find the corresponding [OH-] or [H3O+] at 25°C.

-BARSIC- [3]

Answer:

a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M

Explanation:

14 = pH + pOH
pH = - Log [H3O+]

a) [H3O+] = 1.00 E-10 M

⇒ pH = - Log(1.00 E-10) = 10

⇒ pOH = 14 - 10 = 4

⇒ 4 = - Log[OH-]

⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M

⇒ pH = 4

⇒ pOH = 10

⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M

⇒ pH = 5

⇒ pOH = 9

⇒ [OH-] = 1.0 E-9 M

8 0

3 years ago

Hydrogen sulfide gas H2S and aqueous iron(II) chloride are formed by the reaction of aqueous hydrochloric acid HCl and solid iro

jasenka [17]

Answer:

The balanced chemical equation for this reaction is:

2HCl (aq) + FeS (s) -----> FeCl2 (aq) + H2S (g)

Explanation:

5 0

3 years ago

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