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Ludmilka [50]
3 years ago
10

Acetylene gas C2H2 undergoes combustion to form carbon dioxide and water when it is used in the oxyacetylene torch for welding.

Balance the reaction and answer the following questions.
C2H2(g)+O2(g) ---> CO2(g)+H2O(g)
a. How many grams of water can form if 113g of acetylene is burned?
b. How many grams of acetylene react if 1.10 mol of CO2 are produced?
PLEASE SHOW YOUR WORK!
Chemistry
2 answers:
Tems11 [23]3 years ago
8 0

Answer:

a) 78.19 grams H2O

b) 14.3 grams acetylene

Explanation:

Step 1: Data given

Molar mass of acetylene = 26.04 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

2C2H2 + 5O2 → 4CO2 + 2H2O

Step 3: a. How many grams of water can form if 113g of acetylene is burned?

Calculate moles of acetylene:

Moles = mass / molar mass

Moles = 113.0 grams / 26.04 g/mol

Moles = 4.339 moles

calculate moles of H2O

For 2 moles acetylene we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O

For 4.339 moles of acetylene we'll have 4.339 moles H2O

Calculate mass of H2O

Mass H2O = 4.339 moles * 18.02 g/mol

Mass H2O = 78.19 grams H2O

b. How many grams of acetylene react if 1.10 mol of CO2 are produced?

For 2 moles acetylene we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O

For 1.10 mol CO2 we need 1.10/2 = 0.55 moles of acetylene

Mass acetylene = 0.55 moles * 26.04 g/mol

Mass acetylene = 14.3 grams acetylene

Elenna [48]3 years ago
6 0

Answer:

The answer to your question is below

Explanation:

Reaction

                            C₂H₂ (g) + O₂(g)   ⇒   CO₂ (g)   +  H₂O (g)

                            Reactants         Elements         Reactants

                                    2                       C                       1

                                    2                       H                       2

                                    2                       O                       3

This reaction is unbalance

<u>Reaction balanced</u>

                        <u>   </u><u>2</u><u>C₂H₂ (g) +   </u><u>5</u><u>O₂(g)   ⇒   </u><u>4</u><u>CO₂ (g)   +  </u><u>2</u><u>H₂O (g)</u>

                            Reactants         Elements         Reactants

                                    4                       C                       4

                                    4                       H                       4

                                   10                       O                      10

Now, the reaction is balanced

a) Calculate the molecular mass of acetylene and water

Acetylene = (12 x 2) + (2) = 26 g

Water = (1 x 2) + (1 x 16) = 18 g

                           2(26) g of Acetylene ---------------  2(18) g of Water

                               113 g  of Acetylene --------------   x

                                x = (113 x (2 x 18)) / 2(26)

                                x = 4068 / 52

                             <u> </u>  x = 78. 2 g of water

b)                2 moles of Acetylene ------------  4 moles of carbon dioxide

                   x moles of acetylene ------------  1.10 moles of carbon dioxide

                         x = (1.10 x 2) / 4

                        x = 0.55 moles of acetylene

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7 0
3 years ago
A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
2 years ago
The pH pH scale for acidity is defined by pH = − log 10 [ H + ] pH=-log10[H+] where [ H + ] [H+]is the concentration of hydrogen
balu736 [363]

Answer:

2 51 × 10^-5mol/L

Explanation:

The concentration of hydrogen ions can be calculated using the formula below :

pH = -log [H+]

pH = 4.6

[H+] = ?

[H+] = Antilog (-4.6)

[H+] = 2 51 × 10^-5mol/L

7 0
3 years ago
How many miles of H2O are there in 1.0g of H2O?
Sidana [21]
Molar mass H₂O = 18.01 g/mol

number of moles:

mass of solute / molar mass

<span>1.0 / 18.01 => </span>0.0555 moles

<span>hope this helps!</span>
4 0
2 years ago
How can litmus paper and phenolphthalein be used to tell whether a solution is an acid or a base? Be specific.
MArishka [77]
Both litmus paper and phenolphthalein are used as acid/base (pH) indicators.

Litmus paper:
Litmus paper will turn either blue or red when a drop of solution is added to the paper. Red indicates an acidic solution (pH is <4.5), and blue indicates a basic solution (pH >8.3).

Phenolphthalein:
Phenolphthalein is commonly used during acid/base titrations. When the solution is acidic and the indicator is added, it will remain colorless. If the solution is basic, the phenolphthalein will turn pink.
6 0
3 years ago
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