<span>Prove that KL = EF so in triangle KLM c2 = a2 + b2 which makes triangle EFG a right triangle. </span> <u>Explanation</u> For a right triangle, the sum of the legs squared is equal to the hypotenuse squared. So, in the triangle EFG, a²+b²=c². To make EFG a right triangle at G, we can compared ΔEFG and ΔKLM. Line EF=KL. The correct answer from the choices is; "Prove that KL = EF so in triangle KLM c2 = a2 + b2 which makes triangle EFG a right triangle".