Question

BRAINLIEST!!!

Answer 1

Answer:  $\frac{8}{17}$ or 8:17

Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

$\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}$

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S =  60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

$(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32$

Thus, the side opposite to S = 32 units

Now,  the trigonometric ratio for sin S is given by :-

$\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}$

Hence, the  trigonometric ratio for sin S =$\frac{8}{17}$ or 8:17