Question

The path of a baseball, hit 3 feet above ground, is modeled by the function f(x)=-0.01x^2+x+3, where f(x) represents the vertical height of the bar and X is the horizontal distance. How far across the field, in feet, of the ball travel before hitting the ground? Round to two decimal places

Answer 1

Answer:

Therefore the ball travel 102.92 feet horizontally before hitting the ground

Step-by-step explanation:

Given that, the path of a baseball, hit 3 feet above ground, is modeled by the function

$f(x)=-0.01 x^2+x+3$

where f(x) represents the vertical height of the ball in feet(Assume) and x is the horizontal distance in feet(Assume) .

When the ball hits the ground, then the vertically distance of the ball will be zero, i.e f(x)=0

$\therefore -0.01 x^2+x+3=0$

[Applying quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , here a = -0.001, b=1 and c=3]

$\Rightarrow x=\frac{-1\pm\sqrt{1^2-4.(-0.01).3}}{2.(-0.01)}$

$\Rightarrow x=-2.94, 102.92$

Therefore the ball travel 102.92 feet horizontally before hitting the ground.