y-2 = 3(x+7) put it in y=mx+b form (slope intercept)
y-2 = 3(x+7) distribute 3
y-2 = 3x+21 add 2 to both sides
+2 +2
y = 3x + 23
so now the slope of that is 3 so the new equation has a slope of 3 because parallel slopes are equal.
my new line has a slope of 3 and point (4,2)
so we use point slope formula y-y1 = m(x-x1)
y-2 =3(x-4) put it in y=mx+b form (slope intercept)
y-2 = 3(x-4) distribute 3
y-2 = 3x -12 add 2 to both sides
+2 +2
y = 3x + 10 which is you line slope intercept with parallel slope and contains (4,2)
Answer:
simplified = 8x - 8
Step-by-step explanation:
trust me :)
Answer:
the relation is a function, determine whether the function is ... to y = 2x + 2 a. Il slope = 2 b. ... Change to the slope- intercept form: (show work below) -_y 2x+1. 4- 5= 2(x+3).
Answer:
7
40
the answer is 7 fortyths
working out
3 quarters - 3 eighths = 3 eighths*7 nineths= 7 twentyforths
5 sixths +1 third + 1 half = 10 sixths
7 twentyforths divided by 10 sixths= 7 fortyths
It is just telling you to replace all of the x’s with 1.5 and then solve the equation
