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malfutka [58]
4 years ago
13

What is the answer and how do i solve ?

Mathematics
1 answer:
murzikaleks [220]4 years ago
4 0

\bf -6n+(-12)+4n\implies -6n-12+4n\implies -6n+4n-12\implies -2n-12 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4(n-3)-6n\implies 4n-12-6n\implies -2n-12~~\checkmark \\\\\\ 2(2n-6)\implies 4n-12~~\bigotimes

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Using your equation of f(x)= 5x + 8, evaluate f(5)
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33

Step-by-step explanation:

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3 years ago
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A group of transfer bound students wondered if they will spend the same mean amount on texts and supplies each year at their fou
Jet001 [13]

Answer:

We accept H₀. We don´t have enough evidence to support the difference between the two means

Step-by-step explanation:

Group 1 : Comunity College

Sample:

size  :   n₁  = 54

Sample mean    x₁  = 947

Sample standard deviation     s₁ = 254

Group 2 : Local University

Sample

size  :  n₂  =  66

Sample mean :  x₂  = 1011

Sample standard deviation    s₂  =  87

Significance level  α  = 0,05      α  =  5 %      CI = 95 %

Both samples are with n> 30 so we can use z table for the test

from z-table we find  z(c)  =  1,96

The problem statement establishes to run a hypothesis test to determine if the means are statistically the same  ( or different) then we use two-tail-test

Hypothesis Test

Null Hypothesis                        H₀             x₁   -  x₂  = 0 or    x₁  = x₂

Alternative hypothesis             Hₐ             x₁  -  x₂  ≠  0  or    x₁ ≠ x₂

To calculate

z(s)  =  (  x₁   -  x₂  ) / √ s₁²/n₁  + s₂²/n₂ )

z(s)  =  947  -  1011 / √  (254)²/54   +  (87)² / 66

z(s) = -  64  /√ 1194,74  +  114,68

z(s) =  - 64  / 36,185

z(s) =  - 1,77

Comparing modules of  |z(c)|  and |z(s)|

z(s) < z(c)

Then z(s) is in the acceptance region we accept H₀ . There is not enough evidence to support differences in the means of the two groups

3 0
3 years ago
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