Using your equation of f(x)= 5x + 8, evaluate f(5)
2 answers:
You might be interested in
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
__
If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
-3 11 -1 20
4 -12 -4 -20
-3 -1 -5 0
Bring down the -3,
Multiply -3 * 4
Add 11 and -12
Multiply -1 * 4
Add -1 and -4
Multiply -5 * 4
Add 20 and -20
Answer: The power is reduced by one from the
Dividend. -3x^2 – x - 5
I tried to upload a file also but I don't know if it will show up.
4 -12 -4 -20
-3 -1 -5 0
Bring down the -3,
Multiply -3 * 4
Add 11 and -12
Multiply -1 * 4
Add -1 and -4
Multiply -5 * 4
Add 20 and -20
Answer: The power is reduced by one from the
Dividend. -3x^2 – x - 5
I tried to upload a file also but I don't know if it will show up.