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vazorg [7]
3 years ago
15

What is the 5th term in geometric number pattern where the first term is 4 and the ratio 3/1

Mathematics
1 answer:
Leni [432]3 years ago
4 0
Hello,

a_{1} =4\\\\
 a_{2} =a_{1}*3=4*3=12\\\\
 a_{3} =a_{1}*3^2=4*3^2\\\\
...
 a_{5} =4*3^4=324\\\\
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Just number 4 pleaseeee
Aleksandr [31]

Hello!

The formula is given to you. :)

C = 3.14 • D (diameter; line across a circle that cuts it in half)

C = 3.14 • 21 = 65.94 inches.

Hope I helped! Also, I hope I didn’t answer this too late. ;)

~Destiny ^_^

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Margie's car can go 32 miles on a gallon of gas, and gas currently costs $4$4 per gallon. How many miles can Margie drive on $20
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If she has 32 miles to the gallon, and 20 dollars, then 5*32 gives you your final answer, which is 160.
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Mrs. Carter baked 100 muffins for a bake sale. The muffins were sold in packages in 2. There were 12 muffins left. Write an equa
krek1111 [17]
100 muffins, and 2 in each packages. Therefore, there are 50 packages. However, at the end, there are 12 left, so there must have been 6 packages left. (12/2) 50-6=44. 44*2=88 so 88 muffins were bought. 
6 0
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Please help this is like 40% of my Grade!!
svet-max [94.6K]

Answer:

120

Step-by-step explanation:

supplementary means the angles add up to 180

4 0
3 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
11 months ago
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