I don't really get this if you can help me please help
2 answers:
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Solution:
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm
Answer:
The area of the parallelogram is .
Step-by-step explanation:
Let's rewrite these two vectors:
Let's recall that the area of the parallelogram is the magnitude of the cross product between these vectors.
We can use the Determinant method to find it.
Now, the magnitude is the square root of each component squared. It will be:
Therefore the .
I hope it helps you!