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NISA [10]
3 years ago
6

Calculate the are and perimeter of technology shape at right

Mathematics
2 answers:
sesenic [268]3 years ago
8 0
The answer to this area question is 126 because 6x10=60 and 9x6=54 and 2x3x2=12 so add them and you get 126.
oksano4ka [1.4K]3 years ago
7 0
I hope this helps you

9+6+2+2+3+6+4+10

42

Area= 6.2+3.4+4.10

Area= 12+12+40

Area= 64

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pete is a furniture refinisher. to paint a chest of drawers, he needs 1/2 gallon of paint. he has 1 quart. how many more quarts
bezimeni [28]
Pete needs one more quart of paint, leaving two quarts in total.
7 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
When writing numbers in base 10, we only allow coefficients of 0 through 9. Why is that?​
Margaret [11]

Answer:

Because 0 counts as the first possible number. 0-9 gives you 10 possible numbers.

Step-by-step explanation:

7 0
3 years ago
Does the point (–7, –7) satisfy the equation y = x?
Nataly_w [17]

duh yes obiouslyyyyyyy

8 0
3 years ago
Read 2 more answers
The diameter of a circle is 8 inches. What is the area?
makkiz [27]

Answer:

16 × π in 2

Step-by-step explanation:

the formula to find the area of a triangle is πr^2, you are given the diameter which equals 2r. so split the diameter in half and plug your number in. π4^2

4^2=16

16xπ

8 0
3 years ago
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