Answer:
( 2,1) is the center of dilation and -2 is the scale factor
Step-by-step explanation:
We can use the formula
A' = k( x-a) +a, k( y-b)+b where ( a,b) is the center of dilation and k is the scale factor
(0,0) becomes (6,3)
( 6,3) = k( 0-a) +a, k( 0-b)+b
6 = -ka+a
3 = -kb+b
We also have
(4,0) becomes (-2,3)
( -2,3) = k( 4-a) +a, k( 0-b)+b
-2 =4k -ka+a
3 = -kb+b
Using these two equations
6 = -ka+a
-2 =4k -ka+a
Subtracting the top from the bottom
-2 =4k -ka+a
-6 = ka -a
-------------------
-8 = 4k
Divide by 4
-8/4 = 4k/4
-2 = k
Now solving for a
6 = -ka +a
6 = - (-2)a +a
6 = 2a+a
6 = 3a
Divide by 3
6/3 =3a/3
2=a
Now finding b
3 = -kb+b
3 = -(-2)b+b
3 = 2b+b
3 = 3b
b=1
Sum of interior angles = 180
180 - 60 = 120
120/4 = 30
m<L = m<A = 60
m<M = 30
m<C = m<N = 3(m<M) = 3(30) = 90
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have
![A(t)=100(1+ \frac{.08}{1})^{(1)(15)}](https://tex.z-dn.net/?f=A%28t%29%3D100%281%2B%20%5Cfrac%7B.08%7D%7B1%7D%29%5E%7B%281%29%2815%29%7D%20)
. Simplifying a bit gives us
![A(t)=100(1+.08)^{15}](https://tex.z-dn.net/?f=A%28t%29%3D100%281%2B.08%29%5E%7B15%7D)
and
![A(t)=100(1.08)^{15}](https://tex.z-dn.net/?f=A%28t%29%3D100%281.08%29%5E%7B15%7D)
. Raising that number inside the parenthesis to the 15th power gives us
![A(t)=100(3.172169114)](https://tex.z-dn.net/?f=A%28t%29%3D100%283.172169114%29)
. Multiplying to finish means that A(t) = $317.22
1)b
2)a
Let me know if u want me to show my work