Question

Write a slope-intercept for a line that passes through (-1,5) and (3,-3)

Answer 1

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (-1,5) and (3,-3)

y2 = - 3

y1 = 5

x2 = 3

x1 = - 1

Slope,m = (- 3 - 5)/(3 - - 1) = - 8/4 = -2

To determine the intercept, we would substitute x = - 1, y = 5 and m= - 2 into y = mx + c. It becomes

5 = - 2 × - 1 + c = 2 + c

c = 5 - 2 = 3

The equation becomes

y = - 2x + 3

Answer 2

Answer:

(-3-5)/(3+1)

-8/4= -2

y - 5 = -2(x + 1)

y - 5 = -2x - 2

y= -2x + 3