Answer:
Step-by-step explanation:
The rectangle ABCD has vertices A(-2,2), B(6,2), C(6,3) and D(-2,3).
Now, length of side AB = [6 - (- 2)] = 8 units.
{Since the line AB is parallel to the x-axis, so the length of the segment AB will be the difference between the x-coordinates of the points A and B}
Again, line BC is parallel to y-axis and hence the length BC = (3 - 2) = 1 units.
Therefore, the area of the rectangle ABCD will be (8 × 1) = 8 sq. units. (Answer)
The positions of the letters must correspond. Appropriate choices are ...
∠M ≅ ∠Q
QK ≅ MJ
MN ≅ QR
One way of doing this would be to look at the πr² as if it were a single term. Then we could divide both sides by πr², which leaves h = V/πr².
![\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]](https://tex.z-dn.net/?f=%5Csf%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%204%26%5Csf%206%5C%5C%20%5Csf%205%20%26%5Csf%208%20%5C%5C%20%5Csf%203%20%26%5Csf%20-2%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%202%26%5Csf%203%5C%5C%20%5Csf%201%20%26%5Csf%204%20%5C%5C%20%5Csf%20-5%26%5Csf3%5Cend%7Barray%7D%5Cright%5D)
Just substract corresponding terms
![\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%202%20%26%5Csf%203%5C%5C%20%5Csf%204%26%5Csf4%5C%5C%20%5Csf%208%26%5Csf%20-5%5Cend%7Barray%7D%5Cright%5D)
Option B
The answer is 8
I hope this helps!
