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3 years ago

12

If YC = 4, BC = 6, XY = 5, then AB =

1 answer:

Fittoniya [83]3 years ago

5 0

7.5? well 7 1/2? there is the answer

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What do they say again oh yeah life is hard don't you think so too ?

Shkiper50 [21]

Not really because my life is gooing good

4 0

3 years ago

Read 2 more answers

I need help please helppppppppppppppppppppppp

Marrrta [24]

Given:

A figure of a circle and two secants on the circle from the outside of the circle.

To find:

The measure of angle KLM.

Solution:

According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.

Using intersecting secant theorem, we get

$\angle KLM=\dfrac{1}{2}(Arc(JON)-Arc(KM))$

$(3x-4)=\dfrac{1}{2}(271-(x+6))$

$(3x-4)=\dfrac{1}{2}(271-x-6)$

Multiply both sides by 2.

$6x-8=265-x$

Isolate the variable x.

$6x+x=265+8$

$7x=273$

Divide both sides by 7.

$x=\dfrac{273}{7}$

$x=39$

Now,

$\angle KLM=(3x-4)^\circ$

$\angle KLM=(3(39)-4)^\circ$

$\angle KLM=(117-4)^\circ$

$\angle KLM=113^\circ$

Therefore, the measure of angle KLM is 113 degrees.

5 0

2 years ago

For which function does f decrease by 15% every time x increases by 1

LenaWriter [7]

Answer:

$f(x) = 0.85^{x}$

Step-by-step explanation:

The exponential function that decrease by 15% every time x increases by 1 is given by:

$f(x) = {(1 - 0.15)}^{x}$

We simplify the parenthesis to get:

$f(x) = 0.85^{x}$

Therefore the decrease by 15% every time x increases by 1 is

$f(x) = {0.85}^{x}$

The second choice is correct.

7 0

3 years ago

What multiplication sentence is equal to the division sentence 2/7 divided by 14/3?

Free_Kalibri [48]

I think the answer for your question is B

4 0

3 years ago

Read 2 more answers

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu

iVinArrow [24]

Answer:

$-0.061 < P_1 -P_2< 0.025$

Step-by-step explanation:

Give data:

$n_1 = 350$

$n_2 =250$

$x_1 = 23$

$x_2 = 21$

$\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066$

$\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084$

for 95% confidence interval

$\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025$

$z_{\alpha/2} = 1.96$ from standard z- table

confidence interval for P_1 and P_2 is

$\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}$

$(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}$

$-0.018 \pm 0.043$

confidence interval is

$-0.018 - 0.043 < P_1 -P_2$

$-0.061 < P_1 -P_2< 0.025$

7 0

2 years ago