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2 years ago

Please help me I really need this

Mathematics

1 answer:

pshichka [43]2 years ago

7 0

Answer:

Step-by-step explanation:

Draw a horizontal line at the end of the 8 meter horizontal line.

Find the area of the horizontal rectangle

L = 8 + 3

W = 2

Area = L*w

Area = 11*2

area = 22 m^2

Now do the vertical rectangle

L = 8

w = 3

Area = L*w

Area = 8 * 3

Area = 24 m^2

Total Area = 24 + 22 = 46 m^2

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The product of x and 6 is at least -17

mr_godi [17]

The product of x and 6: 6(x)

is at least -17: ≥ 17

6x ≥ 17 is your answer

hope this helps

7 0

3 years ago

Find an equation of the line with the slope m=6 that passes through the point (4,4). Write the equation in the form Ax + By = C

Ainat [17]

Answer:

Y - 6x = - 20

Step-by-step explanation:

Y = 6x + c

Substituting the value of x and y

4 = 24 + c

Subtracting 24 from both sides

C = - 20

Y = 6x - 20

Subtracting 6x from both sides

Y - 6x =- 20

7 0

3 years ago

What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?

inessss [21]

Answer:

$x+2y-10=0$

Step-by-step explanation:

Consider an equation: $y=mx+c$

Here, m is the slope of the line and c is the y-intercept.

Given equation is $y=2x+3.14$

Here, slope is $m=2$

As product of slopes of two perpendicular lines is equal to $-1$ , slope of the required line is $m_1=\frac{-1}{m}=\frac{-1}{2}$ .

Let $(x_1,y_1)=(2,4)$

Equation of the required line is $y-y_1=m_1(x-x_1)$

$y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0$

8 0

3 years ago

.////////////PLEASE HELPPPPP

Reptile [31]

Answer:

106°

Step-by-step explanation:

Supplementary angles add up to 180°

180°- 74°

= 106°

6 0

3 years ago

Read 2 more answers

Use foil (a + 3)(a - 2)

blsea [12.9K]

Answer:

$\left(a+3\right)\left(a-2\right)=a^2+a-6=$

Step-by-step explanation:

Given expression is $\left(a+3\right)\left(a-2\right)$ .

Now we need to multiply this using FOIL.

F = First $=\left(a\right)\left(a\right)= a^2$

O = Outside $=\left(a\right)\left(-2\right)= -2a$

I = Inside $=\left(3\right)\left(a\right)= 3a$

L = Last $=\left(3\right)\left(-2\right)= -6$

Hence we get :

$\left(a+3\right)\left(a-2\right)=a^2-2a+3a-6=a^2+a-6=$

7 0

3 years ago

Read 2 more answers