Question

Someone solve these equations with working really appreciate it

Answer 1

Answer:

a) $t = \sqrt{\frac{d}{4.9} }$

b) t = 0.3 seconds

c) d = 4.9t²

d) d = 11 cm.

Step-by-step explanation:

One test involves catching a 1 m ruler and measuring the distance, d in meters, that the ruler will travel before being caught, the reaction time t in seconds is then calculated using the formula

$t = \sqrt{\frac{2d}{9.8} }$ .......... (1)

a) the simplified expression is

$t = \sqrt{\frac{d}{4.9} }$ ......... (2)

b) If d = 44 cm = 0.44 meters, from equation (2) we get,

t = 0.299 seconds ≈ 0.3 seconds (Approximate)

c) If we make d as the subject of the equation, then

$t^{2} = \frac{d}{4.9}$

⇒ d = 4.9t² .......... (3)

d) Now, if $t = \frac{0.3}{2} = 0.15$ seconds, then from equation (3) we get,

d = 4.9 (0.15)² = 0.11 meters = 11 cm (Answer)