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Nitella [24]
3 years ago
7

Enter an algebraic equation for the word sentence. Use x as your variable.

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Step-by-step explanation: you need to find out the variable w/ with six to get you to the number 16.

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PLEASE HELP ME! I am stuck on 12 and 13. Thanks in advanced! :)
DiKsa [7]

Answer: 12. 75

13. 105

5 0
2 years ago
One positive number exceeds another by 7​, and their product is 78. Find the numbers.
Alona [7]

Answer:

13 and 6

Step-by-step explanation:

  • 13 • 6 = 78
  • 13 – 6 = 7

3 0
3 years ago
Brainles app doesn’t nothing to help me
castortr0y [4]

Answer:

true but can u help me or u can go to questioncove its better then branily but can u help me pls

Step-by-step explanation:

3 0
3 years ago
1. What is the solution of the system?
andreyandreev [35.5K]

Answer:

The given system of equations has solutions below:

1) The solution is (2,3)

2) The solution is (\frac{-8}{7}, \frac{5}{7})

3) The solution is infinitely many solutions

4) No solution

Step-by-step explanation:

Given system of equation are

-x+2y=4\hfill (1)

-4x+y=-5\hfill (2)

To solve equation by using elimination method

Multiply eqn (2) into 2

-8x+2y=-10\hfill (3)

Now subtracting (1) and (3)

-x+2y=4

-8x+2y=-10

_________________

7x=14

x=\frac{14}{7}

x=2

Substitute x=2 in equation (1)

-2+2y=4

2y=4+2

y=\frac{6}{2}

y=3

Therefore the solution is (2,3)

2) Given equation is

-2x+y=3\hfill (1)

4y-4=x

Rewritting as below

x-4y=-4\hfill (2)

To solve equation by using elimination method

multiply (2) into 2

2x-8y=-8\hfill (3)

Adding (1) and (3)

-2x+y=3

2x-8y=-8

________

-7y=-5

y=\frac{5}{7}

substitute y=\frac{5}{7} in (1)

-2x+\frac{5}{7}=3

-2x=3-\frac{5}{7}

-2x=\frac{21-5}{7}

x=-\frac{8}{7}

Therefore the solution is (\frac{-8}{7},\frac{5}{7})

3) Given equation is 6x+2y=10\hfill (1)

3x+y=5\hfill (2)

equation (1) can be written as

2(3x+y)=10

3x+y=\frac{10}{2}

3x+y=5

Therefore equations (1) and (2) are same therefore it has infinitely many solutions

4) Given equation is -x-2y=14\hfill (1)

-2x-4y=12\hfill (2)

multiply equation (1) into 2

-2x-4y=28\hfill (3)

To solve equation by using elimination method

subtracting (2) and (3)

-2x-4y=28

-2x-4y=12

_______

28\neq -12

therefore it has no solution

4 0
3 years ago
Help me please i need help
Afina-wow [57]

Answer:

its blurry for me sorry

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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