Answer:
6.25n + 3.50
$34.75
Step-by-step explanation:
Break down the important information given in the problem.
The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.
Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.
If you add the amounts together, that is the total cost of ordering lunches.
6.25n + 3.50
(Reember expressions do not have the equal sign).
To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.
6.25n + 3.50
= 6.25(5) + 3.50 Simplify by multiplying 5 and 6.25
= 31.25 + 3.50 Add the two values
= 34.75 Total cost of 5 lunches
Therefore the cost of ordering 5 lunches is $34.75.
81, if you mean 9 Squared.
Answer:
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
Step-by-step explanation:
The null and alternative hypotheses are stated as
H0: u ≥ 1750 i.e the mean is less and equal to 1750
against the claim
Ha: u > 1750 ( one tailed test) the mean is greater than 1750
Sample mean = x`= 1754
Population mean = u = 1750
Population deviation= σ = 65 pounds
Sample size= n = 100
Applying the Z test
z= x`- u / σ/ √n
z= 1754- 1750 / 65/ √100
z= 4/6.5
z= 0.6154
The significance level alpha = 0.1
The z - value at 0.1 for one tailed test is ± 1.28
The critical value is z > z∝.
so
0.6154 is < 1.28
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
8. 6m + 3n
11. 8r^3 - r^2
12. 3h^2 + 8
hope this helps !
