(- 5, - 6 )
for x- coordinate x + 5 = 0 ⇒ x = - 5
given f(x) ± c , the value of c translates the graph vertically up/down by ± c
here c = - 6 , thus graph is shifted down by - 6
thus the vertex = (- 5, - 6)
Answer:
C
Step-by-step explanation:
Since this is an indererminate form, use L'Hopital
d(sint)/dt = cos(t)
d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]
As t --> 0,
cos(0) = 1
(2e^t)/[2e^t - 1] = 2
1/2 is the limit
Answer:
After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
Step-by-step explanation:
We need to complete the square:
x^2 − 4x − 8 = 0
x^2 -2(x)(2)+(2)^2 -8 -4 =0
(x^2 -4x +4) - 12 = 0
(x-2)^2 -12 =0
Now, finding the value of x
(x-2)^2 -12 =0
(x-2)^2 = 12
taking square root on both sides

So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46
Answer:
7x2
Step-by-step explanation:
7x2 is 14 and all the other ones equal 7