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topjm [15]
3 years ago
15

Joshua wants to burn at least 400 calories per day, but no more than 600. He does this by walking and playing basketball. Assumi

ng he burns 4 calories per minute walking, w, and 5 calories per minute spent playing basketball, b, the situation can be modeled using these inequalities: 4w + 5b ≥ 400 4w + 5b ≤ 600 Which are possible solutions for the number of minutes Joshua can participate in each activity? Check all that apply.
40 minutes walking, 40 minutes basketball
60 minutes walking, 20 minutes basketball
20 minutes walking, 60 minutes basketball
50 minutes walking, 50 minutes basketball
60 minutes walking, 80 minutes basketball
70 minutes walking, 60 minutes basketball
Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
4 0

e d g e n u i t y   says its D and F

Kamila [148]3 years ago
3 0
All you have to do is put the walking amount in for w and basketball in for b. Do it for all of these, if it is less than 400 or greater than 600, it is not a solution.

(4 x 40) + (5 x 40) = 360 so reject because it is less than 400.

I'll let you do the rest.
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6x + 5y = 4<br> - 6x + y = 20
Masja [62]

Answer:

x = -8/3

y = 4

Step-by-step explanation:

I assume you want to solve for x and y.

The best way to do this with the two formulas given is elimination. This means add the two equations together.

6x + 5y = 4

-6x + y = 20

The 6 x and -6x will cancel each other. By adding the like terms of the two together you will come out with

6y = 24

Now solve for y by dividing both sides by the 6.

y = 24/6 = 4

Now that we have y, you can plug it into one of the equations and solve for x.

Let's use -6x + y =20.

So plug in the 4 for y to get -6x + 4 = 20

Subtract the 4 from both sides then solve for y by dividing both sides by the -6.

-6x = 16

x = -16/6

You can reduce that down so that x = -8/3.

5 0
3 years ago
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A boat sails 20 miles wast of the port and then 15 miles south to an island how far is the boat from the port if you measure thr
sweet-ann [11.9K]

Answer:

25 miles

Step-by-step explanation:

Given: A boat sail 20 miles west of the port and then 15 miles south to an island.

Picture attached.

The distance from port to island could be measured in a straight line. It will form a hypotenous.

∴ we can use Pythogorean theorem to find the distance.

h^{2} = a^{2} +b^{2}

Where, "a" is adjacent= 20 miles and "b" is opposite= 15 miles.

h^{2} = 20^{2} +15^{2}

⇒ h^{2} = 400+225= 625

⇒h^{2} = 625

⇒h= \sqrt{625}= \sqrt{25^{2} }

We know \sqrt{x^{2} } = x.

∴h= 25\ miles

∴ Distance of Port from the Island is 25 miles.

6 0
3 years ago
Equivalent expression for 7a+21
Mila [183]

Answer:

Step-by-step explanation:

If you factor the expression 7a+21 you can get:

7 × (a+3)

6 0
3 years ago
If EG=10 and EF=4,then FG=?
Alchen [17]
<span>FG = EG−EF
= 10 − 4
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3 years ago
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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
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