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2 years ago

Y+5=-4(x-3) in standard form

Mathematics

1 answer:

katen-ka-za [31]2 years ago

4 0

Answer:

4x + y = 7

Step-by-step explanation:

The standard form of a linear equation is: ax + by = c

That means that we have to transform our equation into that form.

The original equation is: y + 5 = -4(x-3)

and we solve it:

y + 5 = -4x + 12

We move -4x to the left so its sign be possitive

4x +y +5 = 12, we move +5 to the right

4x + y = 12 - 5 , and we simplify

4x + y = 7

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Answer:

the answer is 2.78 percent

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2 years ago

(2)/(3) =( 4)/( 3+x) help give brainliest if correct and explanation please

Juli2301 [7.4K]

Answer:

(2)/(3) =( 4)/( 3+x)

Cross multiply

2*(3+x)= 4*3

Solve bracket

6+2x=12

Subtract 6 from both sides

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3 years ago

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WILL MARK BRAINLY IF CORRECT!

bogdanovich [222]

Answer:

Step-by-step explanation:

The given equation is

$12( - \frac{1}{6}x - \frac{2}{3}y = - 5)$

$5( \frac{2}{5} x + \frac{1}{5} y = - 9)$

When we multiply we obtain the equations:

$- 2x - 8y = - 60$

$2x + y = - 45$

We add both equations to obtain:

$- 7y = - 105$

Divide both sides by -7 to get:

$y = \frac{105}{7} = 15$

6 0

3 years ago

It's from the chapter : "exponents and powers" i need the workings too please help

labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

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3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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2 years ago