How would I solve this?

uysha [10]

13 + 6/6
13 + 1
14

The answer is 14.

Hope this helps!

8 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Lol I NEED HELP!!!! and if you write something thats not the answer then ill REPORT you

Ilya [14]

A) an equal chance or 50-50
There is the same amount of each flavor so it has an equal chance of being cherry or strawberry.

6 0

3 years ago

What is the percent of the figure that is shaded. Drag the correct answer to the box labeled "Correct percentage." 65% 60° .65%

lara31 [8.8K]

Answer:

60

Step-by-step explanation:

6 0

3 years ago

What is the value of x in the equation x - 2/3 + 1/6 = 5/6? 1) 4 2) 6 3) 8 4) 11

Licemer1 [7]

Answer:

$\large\boxed{x=\dfrac{4}{3}=1\dfrac{1}{3}}$

Step-by-step explanation:

$x-\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{5}{6}\qquad\text{multiply both sides by 6}\\\\6x-6\!\!\!\!\diagup^2\cdot\left(\dfrac{2}{3\!\!\!\!\diagup_1}\right)+6\!\!\!\!\diagup^1\cdot\left(\dfrac{1}{6\!\!\!\!\diagup_1}\right)=6\!\!\!\!\diagup^1\cdot\left(\dfrac{5}{6\!\!\!\!\diagup_1}\right)\\\\6x-(2)(2)+1=5\\\\6x-4+1=5\\\\6x-3=5\qquad\text{add 3 to both sides}\\\\6x=8\qquad\text{divide both sides by 6}\\\\x=\dfrac{8}{6}\\\\x=\dfrac{8:2}{6:2}\\\\x=\dfrac{4}{3}$

3 0

3 years ago

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