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11Alexandr11 [23.1K]
2 years ago
11

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill

ion barrels of oil in the well; six years later 1,500,000 barrels remain. Answer the following:
1.) At what rate was the amount of oil in the well decreasing when there were 1,800,000 barrels remaining?
2.) When will there be 150,000 barrels remaining?
Mathematics
1 answer:
ki77a [65]2 years ago
6 0
Based in your question where as the oil is pumped continuously from the well at a rate proportional to the amount of the oil left in the well. so the answer of the following questions are:
A.1 is to 200,000
B.5 years
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Multiply.
Vedmedyk [2.9K]

Answer:

Hello, There! i Noticed that your Question is 4.62 x 106 I'm Suggesting you mean 4.2 x 10 to the 6th power.

4,620,000 Is the Correct Answer My Friend! <3

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Hope this helps!

3 0
2 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%20%3D2x%2B2" id="TexFormula1" title="\sqrt[3]{x+1} =2x+2" alt="\sqrt
Lina20 [59]
The answer is down below

4 0
2 years ago
Over the summer, for every 14 Okra seeds Dana planted, 9 plants grew. If he planted 182 seeds, how many grew into plants?
vova2212 [387]
Simple...

you have: For every 14 seeds that Okra seeds Dana planted 9 of them grew; if he planted 182 seeds..how many grew?

Set up an equation...

\frac{9}{14} = \frac{x}{182}

Cross multiply....

14*x=14x

9*182=1638

14x=1638

\frac{14x}{14} = \frac{1638}{14} =117&#10;

x=117

This means that, for 182 seeds planted, 117 of them grew to be plants.

Thus, your answer.
3 0
3 years ago
Read 2 more answers
Write each repeating decimal using bar
SVETLANKA909090 [29]

Answer:

*The bar is supposed to go on top of the number, but I will put it at the bottom because I don't know how to do it at the top*

a) 0.<u>5</u>

b) 0.<u>13456</u>

Step-by-step explanation:

a) The 5 is repeating so you put the bar on top of the 5

b) The number 13456 is repeated so you put the bar on top of the 13456

6 0
3 years ago
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