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navik [9.2K]
3 years ago
10

If there are 16 ounces in a pound and a baby weighs 10 pounds, how many ounces does the baby weigh?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
5 0
16 times 10 is 160 so 160 ounces
densk [106]3 years ago
3 0
160 oz.  16 ounces x 10 lbs = 160 oz
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DENIUS [597]

Answer:

This is a ratio table,so therefore there is always a pattern.

Step-by-step explanation:

In order to solve,you have to find the constant in the question,such as 30,40,50,and 60.The constant in this example is 10.When the constant is <u>not</u> even,or the numbers are <u>not</u> even,that's the time you pull out your notebook multiplication chart.Look at the numbers,and see if those numbers are on the chart.If all of them are on the chart,then see if one or both of the multiplicable numbers fall under the category of your variables.If all are under one number,then that number is your answer.

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Find an equation of the sphere with center (4, −12, 8) and radius 10. use an equation to describe its intersection with each of
xxMikexx [17]
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36 Intersection in xz-plane: DNE Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84 The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin: x^2 + y^2 + z^2 = 10^2 Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2 (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100 Might as well deal with that double negative for y, so (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 And we have the desired equation. Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane: xy-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (-8)^2 = 100 (x - 4)^2 + (y + 12)^2 + 64 = 100 (x - 4)^2 + (y + 12)^2 = 36 xz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + 12^2 + (z - 8)^2 = 100 (x - 4)^2 + 144 + (z - 8)^2 = 100 (x - 4)^2 + (z - 8)^2 = -44 And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units. yz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (-4)^2 + (y + 12)^2 + (z - 8)^2 = 100 16 + (y + 12)^2 + (z - 8)^2 = 100 (y + 12)^2 + (z - 8)^2 = 84</span>
6 0
3 years ago
What is the answer ​
Mandarinka [93]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
A. 5°<br>B. 35°<br>C. 31°<br>D. 7°​
MrRissso [65]

Answer:

(2x +30) and (3x -5)  (they're opposite to eachother, so they're equal)

2x + 30 = 3x - 5 (set them equal to eachother, then subtract 3x from both side)

-1x = -35 (divide both sides by -1 to isolate x)

x = 35 or B (this is your answer)

Step-by-step explanation:

I hope this helps :))

3 0
3 years ago
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