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2 years ago

Help me please answer neede asap

Mathematics

1 answer:

PolarNik [594]2 years ago

4 0

1 and 1 half oz (I DID IT YAY!!!!)

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8.0x=x^3+3.0x^2 solve for x

katovenus [111]

First of all, move all terms to the same side:

$x^3 + 3x^2 - 8 x = 0$

You can factor an x, which means that $x = 0$ is a solution:

$x(x^2+3x-8)$

This expression is further factorizable if the quadratic equation has any solution. Using the quadratic formula, we can find that they are

$x_{1,2} = -\dfrac{3 \pm \sqrt{41}}{2}$

So, we have

$x(x^2+3x+8) = 0 = \iff x = 0,\quad x =-\dfrac{3 + \sqrt{41}}{2} ,\quad x =-\dfrac{3 - \sqrt{41}}{2}$

5 0

3 years ago

given the equations 9x + (3)/(4)y + 6 and 2x + (1)/(2)y=9 by what factor would you multiply the sencond equation to eliminate y

Paul [167]

Answer:

-3/2

Step-by-step explanation:

If the first equation is 9x +3/4y = 6, then the solution would look like this:

$\left(9x+\dfrac{3}{4}y\right)-\dfrac{3}{2}\left(2x+\dfrac{1}{2}y\right)=(6)-\dfrac{3}{2}(9)\\\\6x=-\dfrac{15}{2}\\\\x=-\dfrac{15}{12}=-\dfrac{5}{4}\\\\2\left(-\dfrac{5}{4}\right)+\dfrac{1}{2}y=9\ \longrightarrow\ y=2\left(9+\dfrac{5}{2}\right)=23$

An appropriate multiplier is -3/2.

4 0

3 years ago

What is the coefficient of fourth term of (-x -3)^5

Alex_Xolod [135]

Answer:

it is 5

Step-by-step explanation:

7 0

2 years ago

2 divided by 5/12= what

AlekseyPX

Answer:

4.8

Step-by-step explanation:

2 ÷ 5/12 = 4.8

Make sure to use a calculator or solve on a piece of paper. :)

6 0

3 years ago

Which expression is the completely factored form of x6−64y3 ?

ss7ja [257]

We are given this

$x^6 -64y^3$

write it as the difference of cubes

$(x^2)^3 -(4y)^3$

use the formula for the difference of cubes

$(x^2-4y) ((x^2)^2+x^2*4y+(4y)^2)$

Now use the formula for the difference of squares as $4y = (2\sqrt{y} )^2$

$(x-2\sqrt{y}) (x+2\sqrt{y}) (x^4+4x^2y+16y^2)$

7 0

3 years ago

Read 2 more answers