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Pie
3 years ago
15

Help me please answer neede asap

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0
1 and 1 half oz (I DID IT YAY!!!!)
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Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1. Shaded area
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z-score value is 1.08

Step-by-step explanation:

The graph depicts the standard normal distribution with mean 0 and standard deviation 1. Shaded area is 0.8599.

So, We are given the shaded area and we need to find the z-score

Looking at the Positive z-score value, which is added in the figure:

z = 1.08

So, z-score value is 1.08

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Say that you own property with a market price of $74,000. The state tax assessors have given it an assessed value of 48% of that
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A

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74,000 x .48 = 35520. 35520 is the amount of property you have to pay for.

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5x-x+2x<br> I need help!!!!
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Rob and casey are batting practice . The table below shows the joint relative frequencies for their misses , fouls ,hits and hom
serious [3.7K]

Answer:

P(Homeroom|Casey)= \frac{1}{21}

P(Rob|Hit)= \frac{23}{50}

Step-by-step explanation:

Hello!

1)

Given the table of probabilities you have to calculate the conditional probability that the result was a homeroom given that Casey was batting.

Following the general model you can calculate this probability as:

P(A|B) = \frac{P(AnB)}{P(B)}

Given two events A and B that are not independent, the probability of A given  that B has occurred is equal to the division between the intersection between A and B by the probability of B.

In terms of this excersise:

P(Homeroom|Casey)= \frac{P(HomeroomnCasey)}{P(Casey)}

Reading the table, the "P(Casey)" is found on the marginals of the table, is calculated as the summation of all battings done by Casey:

P(Casey)= 0.1125+0.05+0.3375+0.025= 0.525

P(Homeroom∩Casey)= 0.025

P(Homeroom|Casey)= \frac{P(HomeroomnCasey)}{P(Casey)}= \frac{0.025}{0.525} = \frac{1}{21}= 0.0476

2)

You have to calculate the probability of the batting being made by Rob given that it was a hit.

P(Rob|Hit)= \frac{P(RobnHit)}{P(Hit)}

The probability of the intersection is

P(Rob∩Hit)= 0.2875

P(Hit)= 0.2875+0.3375= 0.625

P(Rob|Hit)= \frac{P(RobnHit)}{P(Hit)}= \frac{0.2875}{0.625} = \frac{23}{50} = 0.46

I hope this helps!

4 0
3 years ago
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