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Mariana [72]
3 years ago
7

You take a random token from a bag that contains 44? red, 1414? green, and 66? blue tokens. What is the probability your token i

s red?
Mathematics
2 answers:
lakkis [162]3 years ago
6 0

Moderators please delete this answer.

german3 years ago
5 0

Answer:

11/381

Step-by-step explanation:

Not sure what the ? after each number means but I'm going to assume they aren't there

so we need find the number of tokens in all which is

44+1414+66=1524

P(red)=44/1524 now reduce giving P(red)=11/381

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When fractions share the same number on the bottom they have a?
Snezhnost [94]
Fractions that have the same number on the bottom have a "common denominator."
6 0
3 years ago
Part A
olasank [31]
<h3>Answer:</h3>
  • B. f(x) = 3,000(0.85)^x
  • $1566.02
<h3>Step-by-step explanation:</h3>

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

8 0
3 years ago
Which angles are alternate exterior angles with angle 11?
Elena-2011 [213]

The above questions answer is 8 and 14

8 0
3 years ago
I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it
777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer.  The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer.  This time, the car is pushing back on the trailer to slow it down.  So the trailer is pushing forward on the car with an equal and opposite force.  The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0
3 years ago
Write an inequality that represents the verbal expression below.
just olya [345]

Answer:

-3t > 11

Step-by-step explanation:

hope this helps :)

7 0
3 years ago
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