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STALIN [3.7K]
4 years ago
9

What is the simplified from of 72x^16/50x36 assume x =/=0

Mathematics
2 answers:
AleksAgata [21]4 years ago
6 0
6/5x^10 because after you get the answer 36/25x^10 you get the square root which is also half 
frutty [35]4 years ago
6 0
Remember:
\sqrt{x}=x^\frac{1}{2}
\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}   \sqrt{ab}=(\sqrt{a})(\sqrt{b}) (a^b)^c=a^{bc} \frac{x^m}{x^n}=x^{m-n} x^{-m}=\frac{1}{x^m}(ab)/(cd)=(a/c)(b/d)

also remember PEMDAS
so

\sqrt{\frac{72x^{16}}{50x^{36}}}
simplify inside sqrt first
\frac{72x^{16}}{50x^{26}}=  (\frac{72}{50})(\frac{x^{16}}{x^{36}}=  (\frac{36}{25})(x^{16-36})=
(\frac{36}{25})(x^{-20})=

now \sqrt{(\frac{36}{25})(x^{-20})}=  (\sqrt{\frac{36}{25}})(\sqrt{x^{-20}}=  (\frac{\sqrt{36}}{\sqrt{25}})((x^{-20})^\frac{1}{2})=  (\frac{6}{5})(x^{-10})=  (\frac{6}{5})(\frac{1}{x^{10}})=  \frac{6}{5x^{10}}  answer is first option
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3 years ago
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4 years ago
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
4 years ago
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Answer:

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