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EleoNora [17]
3 years ago
11

A project has a 0.44 chance of doubling your investment in a year and a 0.56 chance of halving your investment in a year. What i

s the standard deviation of the rate of return on this investment? (Do not round intermediate calculations. Round your answer to 2 decimal places.)
Business
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

74.46%

Explanation:

Since the project has a chance of doubling investment, it has a chance of making a +100% return. The project also have a chance of losing half of its investment that is -50% return. The expected return E(r) is given by:

E(r) = chance of doubling investment +  chance of losing half of its investment

E(r) = 0.44(100%) + 0.56(-50%) = 0.44(1) + 0.56(-0.5) = 0.44 - 0.28 = 0.16

σ² = 0.44(100% - E(r))² + 0.56(-50%-E(r))² = 0.44(1 - 0.16)² + 0.56(-0.5 - 0.16)² = 0.310464 + 0.243936 = 0.5544

σ = √σ² = √0.5544 = 0.7446 = 74.46%

The standard deviation is 74.46%

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Answer:

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3 years ago
Jayda started a corporation that creates software products for clients. Which statement correctly reflects Jayda’s role in the c
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6 0
3 years ago
Santayana Company purchased a machine on January 1, 2011, for $20,000 with an estimated salvage value of $5,000 and an estimated
Aliun [14]

Answer:

$1,125

Explanation:

Given that,

Cost of machine = $20,000

Estimated salvage value = $5,000

Estimated useful life = 8 years

Depreciation refers to the reduction in the value of the fixed assets of a particular company with the passage of time.

Here, we are using the straight line method,

Annual depreciation is as follows:

= (Cost of machine - Salvage value) ÷ Estimated useful years

= ($20,000 - $5,000) ÷ 8

= $1,875

Depreciation amount for the year 2011 = $1,875

Depreciation amount for the year 2012 = $1,875

Therefore, the book value of the machine at the beginning of January 1, 2013 is as follows:

= Cost of machine - Depreciation amount for the year 2011 - Depreciation amount for the year 2012

= $20,000 - $1,875 - $1,875

= $16,250

Now, the Santayana decides the machine will last 12 years from the date of purchase and we have already deduct the depreciation for the 2 years. So, we need to consider only 10 years for calculating the new annual depreciation.

Salvage value remains the same.

New annual depreciation:

= (Book value at the beginning of 2013 - Salvage value) ÷ Useful life

= ($16,250 - $5,000) ÷ 10

= $11,250 ÷ 10

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8 0
3 years ago
State and city governments have promoted facilities where new businesses can open up shop and share common services such as secr
denis-greek [22]

Answer:

Incubators

Explanation:

In north american context the incubators refers to small places for business provided on low rent.

Basically in the given context, the space for new shops for businesses is given by state and city government, this clearly states that because of involvement of government the prices of such place would be really low as compare to private rental spaces.

This provides that because of this facility incubators will grow.

6 0
3 years ago
Your client has been given a trust fund valued at $1.07 million. He cannot access the money until he turns 65 years old, which i
slega [8]

Answer:

285 Months

Explanation:

n = 30 years  × 12 = 360

percent rate = 5.0 % divided by 12 = 0.417.

Now recalling the statement of time value for money,

We have future value = present value × ( 1 + rate) ∧ n

future value = 1, 070,000  × ( 1 + 0.417 )  ∧ 360

future value = 3.33065667 E 60

At age 65, the value 3.33065667 E 60 will be the  present monthly withdrawal at $28,500.

present value of ordinary annuity, = annuity ( 1 - (1 + r) ∧ -n ÷ r

= 3.33065667 E 60  = 28500 (1 - ( 1 + 0.417) ∧ - n ÷ 0.417

= 3.33065667 E 60 ÷ 28500  = (1 - ( 1 + 0.417) ∧ - n ÷ 0.417

1.168651462 E 56 = (1 - ( 1 + 0.417) ∧ - n ÷ 0.417

we now introduce logs to determine the value of n

Solving further, we discovered that n= 285.

Therefore, the number of months it will last one he start to withdraw the money is 285 month

6 0
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