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Elden [556K]
4 years ago
15

What is the sum of the first eight terms of the series?

Mathematics
2 answers:
Neporo4naja [7]4 years ago
5 0

Answer:

−1066.65

<em>This is the correct answer! I just took the test!! Good luck!!</em>

Ray Of Light [21]4 years ago
3 0
Observe that as the series progresses, the term decreases by 1/4. To show this, observe the first four terms of the series below.

-200 = (1/4)(-800)
-50 = (1/4)(-200)
-12.5 = (1/4)(-50)

Since we have a common ratio, r, of 1/4, we can use the properties of a geometric series to find the 8th term of the series.

Recall that to find the sum of the nth term of a geometric series, we have

S_{n} = a(\frac{1-r^{n}}{1-r})

where a is the first term of the series and r is the ratio.

So, for the first eight terms, we have

S_{8} = -800(\frac{1-(\frac{1}{4})^8}{1- \frac{1}{4}})
S_{8} \approx -1066.65

Therefore, the sum of the 8th series is approximately -1066.65. 

Answer: -1066.65
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Step-by-step explanation:  

Given that;

If V₁ ....... V₄ are in R⁴ and V₃ = 2V₁ + V₂ then {V₁, V₂, V₃, V₄} is linearly dependent.  

Lets {V₁, V₂, V₃, V₄}  are linearly dependent

Then there exist a scalars C₁, C₂, C₃, C₄

So that C₁V₁ + C₂V₂ + C₃V₃ + C₄V₄ = 0

where at least one of the Ci ≠ 0.  

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V₃ is a linear combination of V₁, V₂ and V₄}

that is

Given V₃ = 2V₁ + V₂

⇒ 2V₁ + V₂ - V₃ = 0

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Here, C₁ = 1, C₂ = 1,  C₃ = -1 and C₄ = 0

So that {V₁, V₂, V₃, V₄} is linearly dependent.

therefore option B id the right answer.

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