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3 years ago

What is an equation of the line that passes through the points (-4, -1)(−4,−1) and (6, -1)(6,−1)?

Mathematics

1 answer:

Vlada [557]3 years ago

5 0

$\boxed{y=-1}$

<h2>Explanation:</h2>

In order to solve this problem, let's remember the point-slope form of the equation of a line:

$y-y_{1}=m(x-x_{1}) \\ \\ m:slope \\ \\ (x_{1},y_{1}):A \ point \ on \ the \ line$

We know two points:

$(x_{1},y_{1})=(-4, -1) \\ \\ (x_{2},y_{2})=(6, -1)$

So:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m=\frac{-1-(-1)}{6-(-4)} \\ \\ m=0$

So this is a constant line (slope equals zero). Therefore, every point has a y-coordinate $y=-1$ . In other words, the equation is:

$\boxed{y=-1}$

<h2>Learn more:</h2>

Equation of lines: brainly.com/question/13015874

#LearnWithBrainly

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Step-by-step explanation:

Given

$\sin(A) = \frac{3}{\sqrt {34}}$

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Required

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By comparison:

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$Hypotenuse = \sqrt{34$

So, the Adjacent is:

$Hypotenuse^2 = Adjacent^2 + Opposite^2$

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