Question

What is an equation of the line that passes through the points (-4, -1)(−4,−1) and (6, -1)(6,−1)?

Answer 1

$\boxed{y=-1}$

Explanation:

In order to solve this problem, let's remember the point-slope form of the equation of a line:

$y-y_{1}=m(x-x_{1}) \\ \\ m:slope \\ \\ (x_{1},y_{1}):A \ point \ on \ the \ line$

We know two points:

$(x_{1},y_{1})=(-4, -1) \\ \\ (x_{2},y_{2})=(6, -1)$

So:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m=\frac{-1-(-1)}{6-(-4)} \\ \\ m=0$

So this is a constant line (slope equals zero). Therefore, every point has a y-coordinate $y=-1$. In other words, the equation is:

$\boxed{y=-1}$

Learn more:

Equation of lines: brainly.com/question/13015874

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