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Rashid [163]
3 years ago
5

What is the factorization of the trinomial below 12x^2-x-35

Mathematics
2 answers:
Molodets [167]3 years ago
7 0

Answer:

(4x-7)(3x+5)

Step-by-step explanation:

1) Looking attentively to 12x^{2}-x-35. We need two find two numbers whose product is (12)(-35)=-420 and their sum is -1.

2) These numbers are -21 and 20 their product is -420 and their sum is -1.  Prime factorization might be a good start to find those numbers. Moreover, you can make a list of numbers whose product is -420.

3) Rewrite the trinomial, with those two terms as new <em>b</em> terms.

12x^{2}-x-35=12x^{2}-21x+20x-35

4) Finally, factor them by grouping them:

(12x^{2}-21x)+(20x-35)\Rightarrow 3x(4x-7)+5(4x-7)\Rightarrow (4x-7)(3x+5)

Aleks04 [339]3 years ago
4 0
12x^2-x-35
12x^2-21x+20x-35
3x(4x-7)+5(4x-7)
(4x-7)(3x+5)
Either,
x=7/4
Or,
x=-5/3
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Step-by-step explanation:

We are given;

  • The quadratic equation, x² + 4x - 13 = -8

We are required to solve the equation using the completing square method.

To do this, we use the following steps;

Step 1: We make sure the coefficient of x² is one

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Step 2: Combine the like terms (take the constant term to the other side)

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we get

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Step 3: We add the square of half the coefficient of x on both sides of the equation

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We get;

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Step 4: Put x and 2 under one square and the solve the other side of the equation.

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Step 5: Get the square root on both sides of the equation;

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The solution of the equation is x = 1 or x = -5

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