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Gnom [1K]
3 years ago
9

Solve.

Mathematics
1 answer:
Reil [10]3 years ago
4 0
PerSolve.

After filling a gas tank the odometer read
39 comma 007.239,007.2.
After the next filling it read
39 comma 469.239,469.2.
It took
16.516.5
gal to fill the tank. How many miles per gallon did the driver​ get?
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Dmitri buys 23 pound of mixed nuts, 12 pound of chocolate
timofeeve [1]

Answer:

c. 13.20

Step-by-step explanation:

5 0
2 years ago
Solve the system of equations 7x+10y=36 y=2x+9
Damm [24]

Answer:

x = -2

y = 5

Step-by-step explanation:

Given two equations

1. 7x + 10y = 36

2. y = 2x + 9

Substitute 2x + 9 for y in equation 1.

We have

7x + 10y = 36

7x + 10(2x + 9) = 36

Distribute 10 into (2x + 9)

We have

7x + 10 x 2x + 10 x 9 = 36

7x + 20x + 90 = 36

27x + 90 = 36

Subtract 90 from both sides to eliminate 90 on the left side

27x + 90 - 90 = 36 - 90

27x = -54

Divide both sides by 27 to isolate x

27x/27 = -54/27

x = -2

Now substitute -2 into either equation to get y

Using equation 2, we have

y = 2x + 9

= 2 x -2 + 9

= -4 + 9

= 5

x = -2

y = 5

Check

7(-2) + 10(5) = 36

5 0
3 years ago
Use the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. Scale factor= 3 in:2m.
podryga [215]

Given:

The side of square = 12 in.

Scale factor of enlargement = 3 in : 2 m

To find:

The proportion that is use to solve the side length, x, of the enlarged square.

Solution:

Let, the side of length of enlarged square = x m

In case of enlargement the corresponding sides are proportional.

\dfrac{3}{12}=\dfrac{2}{x}

3x=2\times 12

3x=24

Divide both sides by 3.

x=\dfrac{24}{3}

x=8

Therefore, the required proportion is \dfrac{3}{12}=\dfrac{2}{x} and the side length of the square after enlargement is 8 m.

4 0
2 years ago
Proof that the identities are equal to eachother​
Vikentia [17]

Answer:

Hello, hope this will help:)

6 0
2 years ago
Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

7 0
3 years ago
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